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HT Relay
"Ian Bell" wrote in message
... David Looser wrote: There shouldn't be "god awful current spikes" unless the conduction angle is excessively short, which isn't good for the transformer, the rectifiers or the capacitors. Since both the a.c. conductors are, presumably, co-routed, the magnetic fields will very largely cancel anyway. Well, if you aim initially for 10% ripple then that will be the conduction angle to a first approximation and the current spikes will be 10 times the load current. You were talking about a 200mA DC load, so how big are these spikes then? 3A peak maybe?. hardly sounds like "god awful" to me. And you can use a twisted pair for the ac so that the magnetic fields cancel out. I presume you are not running the power cable close to the audio wiring? Are you using a low-impedance balanced audio input to this amp of yours? if not I suggest that doing that will make far more difference to your hum levels than worrying about ac in the power cable. David. |
HT Relay
On Fri, 25 Dec 2009 09:03:41 -0500, Arny Krueger wrote:
Legacy crowbar - fire a thyratron. If you can guarantee 99.9999% that it will fire whenever you want it to. BTDTGTTS -- John Stumbles Men are from Mars, Women are from Venus and Pop Psychologists are from Uranus |
HT Relay
On Wed, 30 Dec 2009 23:59:58 +0000, Ian Bell wrote:
John Stumbles wrote: On Thu, 24 Dec 2009 14:43:30 +0000, Ian Bell wrote: I am trying to select a relay for a delayed HT switch (which will also discharge the HT when off). Most relays I can find have contacts rated at 250VAC which translates into a peak of about 350V. However, data is scarce on what dc voltage these relays can switch. So far I have found only one that gives a dc current versus voltage curve and that stops at 210V dc (and 200mA) and I really want to be able to switch up to 350V at up to 200mA. The rest just give a dc voltage at max current value. The reason DC switching ratings are lower than AC ratings is that, when breaking a circuit, AC limits the duration of arcing as the current through the contacts drops to zero twice a cycle thus helping to extinguish the arc. With DC the contacts have to open wide enough to extinguish the arc on their own. Indeed, I have found a very informative application note by Tyco that explains wvery well what happens when contacts make and when they break. You say: The PSU is remote and the relay has an interlock to turn off the HT if the PSU HT output lead is disconnected. I need to either disconnect the HT or bleed it very quickly to avoid a possible shock hazard. I assume we have the following setup in the PSU: relay HT+ to -------------o COM LOAD / o o----------- HT+ SUPPLY NC | NO | ----- | R | - discharge resistor ----- | GROUND -----------+---------------- GROUND Not quite, swap the LOAD and SUPPLY and it is correct - in other words the HT supply goes to the common and is switched either to the load or the discharge resistor because nearly all the charge storage is in the HT supply not the load. Could you not arrange it as above? I mean that all the above components are in the PSU box and the node marked 'HT+ to LOAD' is the pole on the output connector of the PSU to which the amplifier/load is connected. Thus as soon as the relay falls back to its rest position the output lead is connected via the discharge resistor to ground (discharging any residual capacitance in the lead electronics) and the internal HT smoothing capacitors within the PSU can be allowed to discharge under their own steam, or with a small, high-value bleed resistor. Doesn't that do what you want? -- John Stumbles Procrastinate now! |
HT Relay
"John Stumbles" wrote in
message On Fri, 25 Dec 2009 09:03:41 -0500, Arny Krueger wrote: Legacy crowbar - fire a thyratron. If you can guarantee 99.9999% that it will fire whenever you want it to. BTDTGTTS If its made with tubes, we can't even guarantee that the entire piece of equipment will work 99.9999% of the time. IOW the criteria of 99.9999% is unrealistically high. |
HT Relay
John Stumbles wrote:
On Wed, 30 Dec 2009 23:59:58 +0000, Ian Bell wrote: John Stumbles wrote: On Thu, 24 Dec 2009 14:43:30 +0000, Ian Bell wrote: I am trying to select a relay for a delayed HT switch (which will also discharge the HT when off). Most relays I can find have contacts rated at 250VAC which translates into a peak of about 350V. However, data is scarce on what dc voltage these relays can switch. So far I have found only one that gives a dc current versus voltage curve and that stops at 210V dc (and 200mA) and I really want to be able to switch up to 350V at up to 200mA. The rest just give a dc voltage at max current value. The reason DC switching ratings are lower than AC ratings is that, when breaking a circuit, AC limits the duration of arcing as the current through the contacts drops to zero twice a cycle thus helping to extinguish the arc. With DC the contacts have to open wide enough to extinguish the arc on their own. Indeed, I have found a very informative application note by Tyco that explains wvery well what happens when contacts make and when they break. You say: The PSU is remote and the relay has an interlock to turn off the HT if the PSU HT output lead is disconnected. I need to either disconnect the HT or bleed it very quickly to avoid a possible shock hazard. I assume we have the following setup in the PSU: relay HT+ to -------------o COM LOAD / o o----------- HT+ SUPPLY NC | NO | ----- | R | - discharge resistor ----- | GROUND -----------+---------------- GROUND Not quite, swap the LOAD and SUPPLY and it is correct - in other words the HT supply goes to the common and is switched either to the load or the discharge resistor because nearly all the charge storage is in the HT supply not the load. Could you not arrange it as above? I mean that all the above components are in the PSU box and the node marked 'HT+ to LOAD' is the pole on the output connector of the PSU to which the amplifier/load is connected. All those components will be in the power supply and the connection to the electronics made as you state. Thus as soon as the relay falls back to its rest position the output lead is connected via the discharge resistor to ground (discharging any residual capacitance in the lead electronics) and the internal HT smoothing capacitors within the PSU can be allowed to discharge under their own steam, or with a small, high-value bleed resistor. Doesn't that do what you want? Pretty much but I was trying to avoid having a bleed resistor permanently across the supply. The PSU has a lot of stored charge and a bleed resistor that takes only a nominal 1% of the load current would take about 5 minutes to discharge it. That in itself is not a problem as the PSU is in an enclosure but when I am testing it, it is a pain to have to wait that long. Cheers Ian |
HT Relay
On Wed, 06 Jan 2010 16:54:59 +0000, Ian Bell wrote:
Pretty much but I was trying to avoid having a bleed resistor permanently across the supply. The PSU has a lot of stored charge and a bleed resistor that takes only a nominal 1% of the load current would take about 5 minutes to discharge it. That in itself is not a problem as the PSU is in an enclosure but when I am testing it, it is a pain to have to wait that long. You seem to be changing the design criteria. As I understood it the design brief (if you like) was that the connections on the outside of the box had to assume safe potentials in the time it took a British Standard Idiot to unplug the connector from the power amp and plug his finger in there instead. Now you seem to be saying you want the potentials within the PSU box to drop to safe levels in some arbitrarily short time so you can stick your finger on conductors inside the PSU box without harm. That's a different problem. I think what I was proposing addresses the original problem, but if you want to make it safe for yourself to prod around in the PSU arbitrarily I suspect that's going to be a non-trivial problem to solve. -- John Stumbles Time flies like an arrow Fruit flies like a banana Tits like coconuts |
HT Relay
In article , John Stumbles
wrote: On Wed, 06 Jan 2010 16:54:59 +0000, Ian Bell wrote: Pretty much but I was trying to avoid having a bleed resistor permanently across the supply. The PSU has a lot of stored charge and a bleed resistor that takes only a nominal 1% of the load current would take about 5 minutes to discharge it. That in itself is not a problem as the PSU is in an enclosure but when I am testing it, it is a pain to have to wait that long. That's a different problem. I think what I was proposing addresses the original problem, but if you want to make it safe for yourself to prod around in the PSU arbitrarily I suspect that's going to be a non-trivial problem to solve. The simplest solution is to have an additional, low value, bleed resistor soldered across the caps during the period of development. Then clip them off when finished, check the behaviour is still OK, and stop. But as you say, your situation as someone developing and testing a circuit is quite different to that of the end user. So the primary requirement is to take due care and use whatever extra safety methods seem relevant during development. Slainte, Jim -- Please use the address on the audiomisc page if you wish to email me. Electronics http://www.st-and.ac.uk/~www_pa/Scot...o/electron.htm Armstrong Audio http://www.audiomisc.co.uk/Armstrong/armstrong.html Audio Misc http://www.audiomisc.co.uk/index.html |
HT Relay
"Ian Bell" wrote in message
... Pretty much but I was trying to avoid having a bleed resistor permanently across the supply. The PSU has a lot of stored charge and a bleed resistor that takes only a nominal 1% of the load current would take about 5 minutes to discharge it. That in itself is not a problem as the PSU is in an enclosure but when I am testing it, it is a pain to have to wait that long. If you switch off the supply to the HT rectifier before the heaters go off then the load current itself will discharge the smoothing capacitors. David. |
HT Relay
John Stumbles wrote:
On Wed, 06 Jan 2010 16:54:59 +0000, Ian Bell wrote: Pretty much but I was trying to avoid having a bleed resistor permanently across the supply. The PSU has a lot of stored charge and a bleed resistor that takes only a nominal 1% of the load current would take about 5 minutes to discharge it. That in itself is not a problem as the PSU is in an enclosure but when I am testing it, it is a pain to have to wait that long. You seem to be changing the design criteria. As I understood it the design brief (if you like) was that the connections on the outside of the box had to assume safe potentials in the time it took a British Standard Idiot to unplug the connector from the power amp and plug his finger in there instead. Now you seem to be saying you want the potentials within the PSU box to drop to safe levels in some arbitrarily short time so you can stick your finger on conductors inside the PSU box without harm. That's a different problem. I think what I was proposing addresses the original problem, but if you want to make it safe for yourself to prod around in the PSU arbitrarily I suspect that's going to be a non-trivial problem to solve. I have not changed the brief. Originally it was simply to delay the switch on of HT until the heaters had warmed up; that and nothing more. It then occurred to me that when the relay dropped out a contact could be used to discharge the PSU caps more rapidly than a bleed resistor. It also occurred to me that I could include the relay coil in a loop in the dc power cable so if it were disconnected the HT would be disconnected too. The delay of the HT until heaters warm up is the requirement. The other 'features' came out as possibilities in using a relay to meet the requirement. Hope that clarifies things. Cheers ian |
HT Relay
David Looser wrote:
"Ian Bell" wrote in message ... Pretty much but I was trying to avoid having a bleed resistor permanently across the supply. The PSU has a lot of stored charge and a bleed resistor that takes only a nominal 1% of the load current would take about 5 minutes to discharge it. That in itself is not a problem as the PSU is in an enclosure but when I am testing it, it is a pain to have to wait that long. If you switch off the supply to the HT rectifier before the heaters go off then the load current itself will discharge the smoothing capacitors. Normally that would be the case but this power supply has a lot more capacitive smoothing than the average and there is still significant stored charge once the heaters have cooled. Cheers Ian David. |
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