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Q of passive equaliser
Suppose you have a simple pot divider consisting of two equal value
resistors, say 10K each. Across the upper one you connect a series LC circuit that resonates at 3KHz or thereabouts. If you drive this network from a low impedance source and plot the response across the bottom resistor, the Q of the resulting peak is not the Q of the series LC but rather is determined by the pair of LC values. For example, choosing l=150mH and C=18nF gives a Q of just over 2. Choosing L= 1.5H and C=1.8nF gives a much higher Q. What I need is a simple means of calculating L and C given the pot divider resistor value and desired Q and f (assuming the Q of the LC itself is much higher). At first sight it might seem the Q should be that of the LC and the 10K resistor but that gives a 2*pi*f*L/R of about 0.3 for the first example above rather than the 2 point something you actually get. Cheers Ian |
Q of passive equaliser
On Tue, 12 Jan 2010 13:43:36 +0000, Ian Bell
wrote: Suppose you have a simple pot divider consisting of two equal value resistors, say 10K each. Across the upper one you connect a series LC circuit that resonates at 3KHz or thereabouts. If you drive this network from a low impedance source and plot the response across the bottom resistor, the Q of the resulting peak is not the Q of the series LC but rather is determined by the pair of LC values. For example, choosing l=150mH and C=18nF gives a Q of just over 2. Choosing L= 1.5H and C=1.8nF gives a much higher Q. What I need is a simple means of calculating L and C given the pot divider resistor value and desired Q and f (assuming the Q of the LC itself is much higher). At first sight it might seem the Q should be that of the LC and the 10K resistor but that gives a 2*pi*f*L/R of about 0.3 for the first example above rather than the 2 point something you actually get. Cheers Ian Why not just Spice model it and play until you get what you want? Or are you simply trying it out to see if you get something that may be useful. There are better controlled ways to do this, you know. Here's a quick analysis for various pot settings from all the way up to nearly the bottom http://www.soundthoughts.co.uk/look/ianseq.png Is that what you were expecting? d |
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