![]() |
|
Cambridge A60
Dave Plowman (News) wrote:
I've been fixing a Cambridge A60 - turned out to be nothing more than both speaker fuses blown. But thought I might as well check the quiescent current while I'm at it. And the method given in the manual is weird - replace the PS DC fuses with 15 ohm resistors and measure the voltage across them. Not having any high watt 15 ohm resistors to hand is there a different way? **Use 1/2 Watt resistors. The Pdiss will be minimal. Better still, use 1 Ohm resistors and make appropriate calculations to compensate. -- Trevor Wilson www.rageaudio.com.au |
Cambridge A60
In article ,
Trevor Wilson wrote: Dave Plowman (News) wrote: I've been fixing a Cambridge A60 - turned out to be nothing more than both speaker fuses blown. But thought I might as well check the quiescent current while I'm at it. And the method given in the manual is weird - replace the PS DC fuses with 15 ohm resistors and measure the voltage across them. Not having any high watt 15 ohm resistors to hand is there a different way? **Use 1/2 Watt resistors. The Pdiss will be minimal. Better still, use 1 Ohm resistors and make appropriate calculations to compensate. I'll post the instructions later just in case there's something there that gives the reason for it using 5 watt resistors. -- *A fool and his money are soon partying * Dave Plowman London SW To e-mail, change noise into sound. |
Cambridge A60
In article ,
Dave Plowman (News) wrote: I'll post the instructions later just in case there's something there that gives the reason for it using 5 watt resistors. Here they are :- 1. Remove power supply fuses(3.15A). 2. Replace fuse with 15ohm wirewound resistors (about 5 watt). 3. Connect a DVM across the resistor in the positive fuseholders place. 4. Turn both IQ presets (RV2, 102) fully anticlockwise. 5. Switch on and observe meter reading. It should be in the region of 0.5 to 0.6V (500 to 600mV). 6. Turn up RV2 until the reading increases by about 0.2V. 7. Now turn up RV102 until the reading increases by a further 0.2V. The meter reading should now be about 1.0V. 8. Leave the amplifier to warm up for a few minutes during which time the reading will rise to approximately 1.4 to 1.6V IT SHOULD NOT BE ALLOWED TO RISE ABOVE 2.0V 9. The amplifier can now be fully checked providing no loads are connected. Aural monitoring can be done using headphones. 10. If all is now okay switch off and replace the 15ohm resistors with 3.15A fast blow-fuses. -- *A person who smiles in the face of adversity probably has a scapegoat * Dave Plowman London SW To e-mail, change noise into sound. |
Cambridge A60
In article , Dave Plowman (News)
wrote: 2. Replace fuse with 15ohm wirewound resistors (about 5 watt). That is interesting. I was wondering if they'd specified 5 Watt because they wanted physically large wirewound resistors to get some inductance as well, for some reason. Slainte, Jim -- Please use the address on the audiomisc page if you wish to email me. Electronics http://www.st-and.ac.uk/~www_pa/Scot...o/electron.htm Armstrong Audio http://www.audiomisc.co.uk/Armstrong/armstrong.html Audio Misc http://www.audiomisc.co.uk/index.html |
Cambridge A60
In article ,
Jim Lesurf wrote: In article , Dave Plowman (News) wrote: 2. Replace fuse with 15ohm wirewound resistors (about 5 watt). That is interesting. I was wondering if they'd specified 5 Watt because they wanted physically large wirewound resistors to get some inductance as well, for some reason. Dunno - I'd never seen this method used hence bringing it up. If I'd suitable 5 watt resistors lying around I'd not have bothered. ;-) -- *My designated driver drove me to drink Dave Plowman London SW To e-mail, change noise into sound. |
Cambridge A60
"Jim Lesurf is a know nothing ****** " 2. Replace fuse with 15ohm wirewound resistors (about 5 watt). That is interesting. I was wondering if they'd specified 5 Watt because they wanted physically large wirewound resistors to get some inductance as well, for some reason. ** How ****ing pig ignorant & stupid. FFS - break a 5W WW resistor open take a ****ing look it it. IDIOT !!!! .... Phil |
Cambridge A60
In article , Dave Plowman (News)
wrote: In article , Jim Lesurf wrote: In article , Dave Plowman (News) wrote: 2. Replace fuse with 15ohm wirewound resistors (about 5 watt). That is interesting. I was wondering if they'd specified 5 Watt because they wanted physically large wirewound resistors to get some inductance as well, for some reason. Dunno - I'd never seen this method used hence bringing it up. If I'd suitable 5 watt resistors lying around I'd not have bothered. ;-) I can see a point of having a bigger resistance since it makes the current easier to monitor. And will drop the rail if a lot of current is drawn. But having in the past both measured the inductance of resistors and taken them apart I know that some wirewound types are far from being a plain resistance. Not all were non-inductively wound. And some had a fair bit of shunt capacitance. Who knows, maybe it is the shunt capacitance they are hoping for. :-) Slainte, Jim -- Please use the address on the audiomisc page if you wish to email me. Electronics http://www.st-and.ac.uk/~www_pa/Scot...o/electron.htm Armstrong Audio http://www.audiomisc.co.uk/Armstrong/armstrong.html Audio Misc http://www.audiomisc.co.uk/index.html |
Cambridge A60
On 15/06/2011 15:44, Phil Allison wrote:
"Jim Lesurf is a know nothing ******" 2. Replace fuse with 15ohm wirewound resistors (about 5 watt). That is interesting. I was wondering if they'd specified 5 Watt because they wanted physically large wirewound resistors to get some inductance as well, for some reason. ** How ****ing pig ignorant& stupid. FFS - break a 5W WW resistor open take a ****ing look it it. IDIOT !!!! As usual Phil cuts to the chase. |
Cambridge A60
"atriage" Phil Allison wrote: "Jim Lesurf is a know nothing ******" 2. Replace fuse with 15ohm wirewound resistors (about 5 watt). That is interesting. I was wondering if they'd specified 5 Watt because they wanted physically large wirewound resistors to get some inductance as well, for some reason. ** How ****ing pig ignorant& stupid. FFS - break a 5W WW resistor open take a ****ing look it it. IDIOT !!!! As usual Phil cuts to the chase. ** If you open a 5W, WW resistor - there is a ceramic tube inside with a short coil of resistance wire wound on it. The tube is about 3.5 mm in diameter, 20mm long and there might be 12 turns on it. Using an on-line calculator gives 70 nH of inductance. Using the formula XL = 2 . pi. F. L - F comes out as ** 17MHz ** for a reactance of 15 ohms. Do the same calc for a 15 ohm film resistor of 2W or 3W rating and the answer is much the same. Bonkers. ..... Phil |
All times are GMT. The time now is 12:10 AM. |
|
Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.0.0
Copyright ©2004-2006 AudioBanter.co.uk