Jim Lesurf wrote:

In article ,
nsj wrote:

David Leadbetter wrote:

Sorry if this is O/T.

Has anyone noticed the dreadful interference either side of Radio5 - 909
metres.


909kHz, not metres. Divide by 300 to get wavelength from frequency in kHz.


The above wording seems misleading to me as it seems to say that

wavelength = freq/300

which cannot be correct as it implies the wavelength scales with the
frequency. Should be that one varies in inverse proportion with the other.
Higher frequency means smaller wavelength. The '300' may be wrong as well -
depends on the units you require for both parameters.

I wish I could have used the "it was late" response. Sadly, that doesn't
carry much weight for a post made at 17:26

c = fl
l = c/f
l = 3x10^8/909x10^3
l = 3x10^8/9.09x10^5
l = 3x10^3/9.09
l = 330m

grin

That'll teach me to be a smart-arse.

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