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Old November 12th 05, 07:53 PM posted to uk.rec.audio
housetrained
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Posts: 52
Default Radford crossover problems

WRONG I don't mean bi-amp ( which requires an amp for each cone.) Bi-wire
means you allocate a wire for each cone - from the same amp output. Seems
strange but it works. The separate wires stop interference.

--
John the West Ham fan


"harrogate2" wrote in message
...

"sbring" wrote in message
oups.com...

housetrained wrote:
Why not bi-wire direct thus by-passing the crossovers altogether?


Could you explain this a little? I don't understand.

Sven


Actually he means bi-amp, that is apply the LF/HF filtration at
signal/line rather than loudspeaker/power level. Such filters are
small, you can even build them yourself if you can use a soldering
iron. The only downside is that you need one power amp per speaker per
frequency range, albeit they don't need anything like as much power as
there is no crossover loss. I.e. if you have a two-way speaker, a
woofer and a tweeter, then you will need two amps: if you have a
squaker as well in a three-way system, then you will need three amps.
However if you have two drivers per frequency range (i.e. six speakers
in the cabinet in pairs) then you still only need three amps. The same
quantity is needed again for the other speaker box.

Bi-wiring is when you feed seperate cables from the amp to the
speaker, but you still need some form of crossover to feed the correct
frequencies to each loudspeaker driver.


--
Woody

harrogate2 at ntlworld dot com