In article , Dave Plowman (News)
wrote:
In article , Bob Latham
wrote:
The amplifier will see the capacitance of two speaker cables and in
this sense they are in parallel which will add the capacitance of
each. The cables are not connected together at the speaker end and
don't cover the same frequency spectrum so in no sense are they in
parallel for current flow to the speaker.

Unless the cables have significant capacitance inductance resistance etc
they are effectively in parallel at the speaker end. And are carrying
exactly the same signal since they are paralleled at the source of that
signal.

I am trying to recall how a Flag Officer is supposed to comment when his
Admiral says something that perhaps isn't quite correct... :-)

If the amplifier has an o/p impedance that is essentially 'nil' then the
speakers won't be affected by cable capacitance. The individual units will
be affected by the individual series resistance and inductance of the cable
connected to that unit - but not that connected to the other unit. If the
amp has a non-zero o/p impedance then there will be a resulting
interaction.

The 'signals' involve both current and voltage. The amp may be asserting
the same voltage pattern at the (common) amp end of the bi wired cables.
But the currents in the cables may differ, and the individual cable-speaker
impedance interactions are in different paths.

Please see the webpages I've referred to previously as they should clarify
this topic.

Slainte,

Jim

--
Electronics http://www.st-and.ac.uk/~www_pa/Scot...o/electron.htm
Audio Misc http://www.st-and.demon.co.uk/AudioMisc/index.html
Armstrong Audio http://www.st-and.demon.co.uk/Audio/armstrong.html
Barbirolli Soc. http://www.st-and.demon.co.uk/JBSoc/JBSoc.html