bi-wire config question
Jim Lesurf wrote:
In article , Serge Auckland
wrote:
Bob Latham wrote:
The change in "total" resistance comes from the doubling of the 'speaker
cables, and therefore a halving of the total resistance. As each
'speaker cable now carries a lower current, the already small loss down
each 'speaker cable becomes smaller still.
Serge: Are you assuming the two cables are being connected together at
*both* ends? If so, I'd agree with what you say. But if not, the statement
that the "total" resistance halves leads to the question - which device in
the system experiences a current that passes through this "total"
resistance?
I just re-read what I wrote earlier, and it's complete tosh! Crossover
distortion of the brain.... The amp would still see each individual
drive unit and its crossover components, and each part of the cable
would still carry the same individual current to each drive unit.
Consequently, there would be no change in "total" resistance.
S.
I can see that the amp would be such a device. But not the individual
speaker units.
[snip]
There's no mystery to any of this, it's another example of the hi-fi
fraternity accepting what some mags and shops tell them as truth,
without any engineering rigour being applied.
With this I am inclined to agree. The curious thing is that I did the
webpages I've referred to back in 2002. Perhaps I should try writing a
magazine article on this sometime as it continues to be a 'mystery' in the
magazines... :-)
Slainte,
Jim
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