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Output classes A and AB
In article .com,
Andre Jute wrote: On Oct 25, 7:40 am, Eeyore wrote: John Byrns wrote: Patrick Turner wrote: Cancelation of even order harmonics occurs in amps working in class AB during that part of the wave forms which are in class A, ie, the bits either side of the zero crossing. But once each tube moves into cut off, nothing is cancelled. Patrick, I'm surprised to hear you say this. What are you trying to tell us, that the even order harmonics are only cancelled during those parts of the cycle when both tubes are conducting, but that the even order distortion components reappear during those parts of the cycle when only one tube is conducting? If you actually believe that you should go back to the books and study the theory of harmonic distortion more carefully. I hope you didn't get this notion from the RDH4, I haven't read the RDH4's harmonic distortion explanation, but if this is what it says I have just lost any respect I had for the book. In a perfectly balanced PP amplifier the even order harmonic distortion is completely cancelled even when the tubes are cut off for parts of the cycle. I'd love to know how that happens. There's no cancellation of ANYTHING once one side has ceased conducting ! Graham Holy ****! Did I say yet that Poopie is ignorant and incompetent? Nah, nobody can be that stupid and uninformed about tube basics. There are a lot of "stupid and uninformed" people around, there are at least three people involved in this discussion that have expressed this same belief as Eeyore, they are Multi-grid, Patrick Turner, and Eeyore. Regards, John Byrns -- Surf my web pages at, http://fmamradios.com/ |
Output classes A and AB
On Oct 25, 4:16 am, "Arny Krueger" wrote:
"Don Pearce" wrote in message Andre Jute wrote: Now this poor dumb slow learner Poopie Stevenson, an embarrassment to everyone who comes into contact with him, claims to know more than the RDH4! Yo, Poopie, in the RDH4 (Newnes 1997) on p 545 we find this nugget of authoritative information by F. Langford-Smith B.Sc. B.E. himself: "Class AB operation indicates overbiased conditions, and is used only in push-pull to balance out the even harmonics." No such thing in the RDH4 at hand. Do you just lie from habit, Krueger, or are you incapable of using the contents list or the index of a reference book? The reference is from RDH4, Chapter 13, Section 1 (ii) Classes of Operation. Unsigned out of contempt |
Output classes A and AB
"John Byrns" wrote in message ... In article , "Arny Krueger" wrote: Actually, there is cancellation regardless of whether one side has ceased conducting or not, because the cancellation comes from the fact that the transfer functions of the two sides are identical but opposite. During the portion of the wave where both sides conduct, there may be cancellation of odd order distortion. Are you sure about this? yes. This looks about right: http://dave.uta.edu/dillon/ee5301/lecture11.htm In school I was taught the law of half-wave symmetry. Any wave, no matter how distorted, that has matching halves has no even-order distortion. Aren't there two symmetry laws, I can never remember the second one, or is it the first? Thanks for the memory jog. Please see the reference. There are lots of symmertry laws! A wave that is composed of one half of any kind and the other half is zero, has only even-order distortion. Could you say that again please? A wave that is composed of one non-zero half wave of any kind, and the other half is nothing (zero), has only even-order distortion. |
Output classes A and AB
Poopie Stevenson aka Eeyore
wrote: Andre Jute wrote: Eeyore wrote: Andre Jute wrote: All of that follows logically from Poopie's absurd redefinition of Class A as a Class in which "the output device(s)never cease conducting *under any signal condition*," (emphasis added). It's ludicrous. It's actually the only accurate definition. I've already demonstrated several times that your words "under any signal condition" make your definition grossly inaccurate. But you're an ignorant **** and what you say is a load of ********. Even when I'm right? Tsch, tsch, Poopie. That's not even an original thought. Ron Bales had it first. "In a Class A circuit, the amplifying element is biased so the device is always conducting to some extent"http://en.wikipedia.org/wiki/Electronic_amplifier#Class_A You're blowing smoke through your fat arse, Poopie. That reference doesn't say anything about "under any signal condition." Even Wikipedia isn't as misinformed as you are. That must be a new record for you. You're confusing cause and effect but your brain is too addled to understand the difference. It still wasn't me who said "under any signal condition". It is still you who sstupidly said "under any signal condition", thereby voiding the rest of the definition of Class A operation. Graham You're a clown, Poopie. Wiki in, Poopie out. Same as GIGO. Unsigned out of contempt |
Output classes A and AB
On Oct 25, 2:12 am, Eeyore
wrote: Andre Jute wrote: Eeyore wrote: You really should constrain yourself to talkind about stuff you understand. Which would seem not to be very much going by your posting history. Me? Come on, Poopie, I'm not the one who claimed for several days that a Class A stage is one in which "the output device(s)never cease conducting *under any signal condition*." You're the one who committed that stupidity, and so many others. And * so many others* too eh ? You do rather make a habit of being wrong, Poopie. Even your mother noticed that. Ever consided we might actually be right ? Of course I have. I am a connoisseur of unlikely and bizarre events. If you are ever unequivocally right in an argument with me, I get to win a couple of thousand Euro that I've bet on the statistically probability that nobody can be wrong *all* the time. Why, even a broken clock shows the right time twice every day! You're a ****ING CRETIN Joot. Go back to the miserable hole you crawled out of. No point in abusing me, Fatso; it won't make me any less right or you any less wrong. Graham AKA Poopie for a good reason. Why don't you share it with us. The reason for your name is surely the one thing you do know. Hey, Poopie, aren't you the same Graham Stevenson clown who announced three or four years ago that he came to RAT "to be on Jute's arse". You will let me know when you start, won't you. Andre Jute Rodeo rider |
Output classes A and AB
On Oct 25, 1:17 pm, John Byrns wrote:
In article .com, Andre Jute wrote: On Oct 25, 7:40 am, Eeyore wrote: John Byrns wrote: Patrick Turner wrote: Cancelation of even order harmonics occurs in amps working in class AB during that part of the wave forms which are in class A, ie, the bits either side of the zero crossing. But once each tube moves into cut off, nothing is cancelled. Patrick, I'm surprised to hear you say this. What are you trying to tell us, that the even order harmonics are only cancelled during those parts of the cycle when both tubes are conducting, but that the even order distortion components reappear during those parts of the cycle when only one tube is conducting? If you actually believe that you should go back to the books and study the theory of harmonic distortion more carefully. I hope you didn't get this notion from the RDH4, I haven't read the RDH4's harmonic distortion explanation, but if this is what it says I have just lost any respect I had for the book. In a perfectly balanced PP amplifier the even order harmonic distortion is completely cancelled even when the tubes are cut off for parts of the cycle. I'd love to know how that happens. There's no cancellation of ANYTHING once one side has ceased conducting ! Graham Holy ****! Did I say yet that Poopie is ignorant and incompetent? Nah, nobody can be that stupid and uninformed about tube basics. There are a lot of "stupid and uninformed" people around, there are at least three people involved in this discussion that have expressed this same belief as Eeyore, they are Multi-grid, Patrick Turner, and Eeyore. From Eeyore (Poopie Stevenson) I expect only the worst; he says whatever comes into this head as the opposite of what is said by someone he dislikes, without any reference to the facts in electronics; I have made a separate thread to illustrate that Poopie is joined in this perversity by Pearce and Krueger. I've given up reading Cuddles Multi-grid's posts; it is too wearing to think up new ways of explaining the same simple thing to him over and over again. Patrick is entitled to a mistake now and again; he makes so few. I saw the above and knew you would call him on it, so I read on before I wasted my own time telling Patrick he'd better explain himself -- and there you were, pointing out the faux pas. Actually, I regret that Patrick is both honest and not as slippery with words as some we have seen here, or we could have had a dingdong as he tried to explain it away without admitting he was wrong. I expect he will just say he slipped up. I actually find Patrick's total ignorance of woodsawing the most amazing thing in this thread -- especially considering that we have a fellow with real expertise (and ruler braces) on board RAT: Iain Churches. Regards, John Byrns -- Surf my web pages at, http://fmamradios.com/ Andre Jute Visit Jute on Amps at http://members.lycos.co.uk/fiultra/ "wonderfully well written and reasoned information for the tube audio constructor" John Broskie TubeCAD & GlassWare "an unbelievably comprehensive web site containing vital gems of wisdom" Stuart Perry Hi-Fi News & Record Review |
Don's limp driver Output classes A and AB
On Oct 25, 10:29 am, (Don Pearce) wrote:
On Thu, 25 Oct 2007 13:43:56 GMT, John Byrns wrote: In article , (Don Pearce) wrote: Can you overdrive a class A amp to cutoff? Yes, it is painfully easy. In my experience what happens when you overdrive a class A amp is that one device saturates, and the other sticks with its normal bias condition. No, the coupling capacitor charges up as a result of grid current shifting the bias point so that cutoff becomes even easier. There is no circumstance in which I have ever managed to put a class A amplifier output device into cutoff. You haven't tried very hard then. The designs I have used must have been better matched in drive level between the driver and output stages. They tended to limit almost simultaneously so that the drive level to the output stage did not go on rising as the input signal increased, just squared off. As I say, I never saw an output valve go into cutoff. d -- Pearce Consultinghttp://www.pearce.uk.com A driver stage that limp must be fertile ground for Miller, so how's your bandwidth, Don? Andre Jute Lateral thinker and skunk-trapper |
Output classes A and AB
In article ,
"Arny Krueger" wrote: "John Byrns" wrote in message ... In article , "Arny Krueger" wrote: Actually, there is cancellation regardless of whether one side has ceased conducting or not, because the cancellation comes from the fact that the transfer functions of the two sides are identical but opposite. During the portion of the wave where both sides conduct, there may be cancellation of odd order distortion. Are you sure about this? yes. This looks about right: http://dave.uta.edu/dillon/ee5301/lecture11.htm Which type of symmetry discussed in that lecture is suggestive of canceling odd order distortion? Some of the cases presented appear to have a period of T/2 rather than T which confuses the issue. Also I am assuming that the output devices in our idealized amplifier have a single valued input to output function, which somewhat constrains the types of symmetry the output signal can have. In school I was taught the law of half-wave symmetry. Any wave, no matter how distorted, that has matching halves has no even-order distortion. Aren't there two symmetry laws, I can never remember the second one, or is it the first? Thanks for the memory jog. Please see the reference. There are lots of symmertry laws! A wave that is composed of one half of any kind and the other half is zero, has only even-order distortion. Could you say that again please? A wave that is composed of one non-zero half wave of any kind, and the other half is nothing (zero), has only even-order distortion. You took me too literally, I wondered if you would and left the question so it would allow simply saying it again. If you actually mean what you seem to be saying, you are wrong, as a trivial example will easily demonstrate. Or are you talking about the wave from each of the two devices, which is why I asked for clarification? Regards, John Byrns -- Surf my web pages at, http://fmamradios.com/ |
Output classes A and AB
Eeyore wrote: Patrick Turner wrote: Eeyore wrote: Andre Jute wrote: Poopie Stevenson aka Eeyore wrote: John Byrns wrote: Andre Jute wrote: Historically, the original purpose of Class AB was to annihilate the second harmonic which before made up such a very large part of the THD, while still allowing beam tubes and pentodes to give much larger power than available before. Andre, why was Class AB necessary to annihilate the second harmonic, didn't Push Pull operation already annihilate the second harmonic irrespective of the class of operation? Yes, you are right. It does. The SOLE purpose of AB is to produce larger power outputs using the same tubes. Now this poor dumb slow learner Poopie Stevenson, an embarrassment to everyone who comes into contact with him, claims to know more than the RDH4! Yo, Poopie, in the RDH4 (Newnes 1997) on p 545 we find this nugget of authoritative information by F. Langford-Smith B.Sc. B.E. himself: "Class AB operation indicates overbiased conditions, and is used only in push-pull to balance out the even harmonics." It's the push-pull that cancels those harmonics YOU UTTER CRETIN ! A Class **A** push-pull output stage will do that too. AB operation has NOTHING to do with distortion cancellation. But it does. ONLY because AB working is by design push-pull. The same thing happens in long-tailed pairs. the distortion cancellation is NOTHING whatever to do with AB operation. Well, sure, LTP low 2H output relies on each device having its own 2H cancelling with the other one. They cannot work in class AB as neither of them can cut off, because of the large common cathode resistance. But in a power output stage, there IS in effect a large LTP working until one tube does cut off, ie, have Ia less than 1/10 the idle value, and then the cancelation is zero, but the voltage output is the sum of two devices acting non linearly upon each +ve and -ve 1/2 waves. In fact one can set up an output pair of tubes with a commonened cathode constant current sink, and have the output stage ONLY able to work in class A, and if one tube cuts off there is no output in the anode circuit connected to the OPT with CT. Such a class A output stage has been touted as being the purest form of class A PP by Allen Wright. It can be driven by having SE drive to one grid of the PP pair with the other grid gounded. I have used the principle for driver stages. Patrick Turner. d for the CCS as the common cathode e Graham |
Output classes A and AB
John Byrns wrote: In article , Patrick Turner wrote: Cancelation of even order harmonics occurs in amps working in class AB during that part of the wave forms which are in class A, ie, the bits either side of the zero crossing. But once each tube moves into cut off, nothing is cancelled. Patrick, I'm surprised to hear you say this. What are you trying to tell us, that the even order harmonics are only cancelled during those parts of the cycle when both tubes are conducting, but that the even order distortion components reappear during those parts of the cycle when only one tube is conducting? In effect the even order distortions DO re-appear when the amp moves to class AB. Its because of the mismatch between the two tubes, and each has slightly or greatly different gm, so each +ve and -ve half of the waves are amplified by a different amount, and hence you get even order generated in the output from across the whole primary or secondary of the OPT. The odd order is also there, and usually dominates the distortion profile, so that in a typical 45 watt amp using a pair of EL34 in UL and class AB, there might be very low 2H in the first 5 watts, but just below clip its 1%, and with maybe 4% 3H. If you actually believe that you should go back to the books and study the theory of harmonic distortion more carefully. I hope you didn't get this notion from the RDH4, I haven't read the RDH4's harmonic distortion explanation, but if this is what it says I have just lost any respect I had for the book. In a perfectly balanced PP amplifier the even order harmonic distortion is completely cancelled even when the tubes are cut off for parts of the cycle. It sounds like you have become one of Multi-grid's sock-puppets. Not enough ppl have taken their own measurements of typical amplifiers to know as much as what is written in RDH4 by demonstrating it all to themselves. PP amps have much lower 2H at all levels than the same tubes used in SE parallel. But 2H IS produced due to tube mismatches. But I have used tubes which are well matched and 2H is sometimes very low right up to clipping, and usually the 3H is at least 15dB greater. But in old amps where the tubes ahve aged, 2H in PP amps can be as great as 3H, and this is easy to find in such amps as Quad-II, where the old input pair of pentodes has a large differential 2H content, and so does the unmatched KT66, and reversing positions of the input pair will either cancel or add to the 2H and the difference in 2H after such tube swaps can be 15dB. The two non linear current waves in the tubes of the AB pair are summed, and the VOLTAGE total is substantially linear, with a small fraction of the THD of each tube's current wave. And that small fraction is very small indeed, approaching zero to be precise, for the even harmonics. Its magic, but it works for most ppl. It's not magic, it's just math. Its magical luck if you have well matched output tubes. The math is used to describe it only... Where you have a fixed bias PP amps and a pair of 10 ohm R as series cathode resistors, you can see the curent waves on the CRO by monitoring voltage across each 10 ohms. At high AB PO, the wave looks like that of a half wave rectifier. if you connect a 1:1 transformer from cathode to cathode, the secondary voltage looks fine. Its a sine wave but with many harmonics at low level like the anode to anode signal voltage, except that it increases with a lower load and is thus a source of current FB voltage and can be used as positive current FB to reduce Rout. (( There are bothers with a set up like this because this increases THD/IMD, but with NFB used as well the THD/IMD can be much reduced, but Rout made to be very low, or near 0.0 ohms, or even negative..)) Patrick Turner. Regards, John Byrns -- Surf my web pages at, http://fmamradios.com/ |
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