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Output classes A and AB
In article ,
"Rudy" wrote: for the purpose of loadline analyses, that is a fair approximation. for analyzing the actual working mechanism, it lacks accounting for the element of time, as the transformer actually stores energy comparable to a fast rotating heavy object storing rotational impulse so in case a tube is cutoff, it's plate will happily follow to wherever that winding will take it. (well, not so happy when certain V's are exceeded, perhaps:) Huh, wouldn't the transformer store energy more like a spring does, after all the schematic symbols are very similar? If "the transformer actually stores energy comparable to a fast rotating heavy object" wouldn't that cause a 6 dB/octave roll-off, resulting in a serious loss of high frequencies? Regards, John Byrns -- Surf my web pages at, http://fmamradios.com/ |
Output classes A and AB
"John Byrns" wrote in message ... : In article , : "Rudy" wrote: : : for the purpose of loadline analyses, that is a fair approximation. : for analyzing the actual working mechanism, it lacks accounting for : the element of time, as the transformer actually stores energy : comparable to a fast rotating heavy object storing rotational impulse : so in case a tube is cutoff, it's plate will happily follow to wherever : that winding will take it. : (well, not so happy when certain V's are exceeded, perhaps:) : : Huh, wouldn't the transformer store energy more like a spring does, : after all the schematic symbols are very similar? : : If "the transformer actually stores energy comparable to a fast rotating : heavy object" wouldn't that cause a 6 dB/octave roll-off, resulting in a : serious loss of high frequencies? : : : Regards, : : John Byrns : err, yes, i just wanted to emphasize the 'flux doesn't stop on a dime' aspect. :-) Rudy |
Output classes A and AB
On Oct 31, 4:46 pm, John Byrns wrote:
In article , "Rudy" wrote: for the purpose of loadline analyses, that is a fair approximation. for analyzing the actual working mechanism, it lacks accounting for the element of time, as the transformer actually stores energy comparable to a fast rotating heavy object storing rotational impulse so in case a tube is cutoff, it's plate will happily follow to wherever that winding will take it. (well, not so happy when certain V's are exceeded, perhaps:) Huh, wouldn't the transformer store energy more like a spring does, after all the schematic symbols are very similar? If "the transformer actually stores energy comparable to a fast rotating heavy object" wouldn't that cause a 6 dB/octave roll-off, resulting in a serious loss of high frequencies? Regards, John Byrns -- Surf my web pages at, http://fmamradios.com/ Yes it does. This is from the leakage inductance. Things come to a complete stop when leakage L and capacitance resonate...:) cheers, Douglas |
Output classes A and AB
In article .com,
Multi-grid wrote: On Oct 31, 4:46 pm, John Byrns wrote: In article , "Rudy" wrote: for the purpose of loadline analyses, that is a fair approximation. for analyzing the actual working mechanism, it lacks accounting for the element of time, as the transformer actually stores energy comparable to a fast rotating heavy object storing rotational impulse so in case a tube is cutoff, it's plate will happily follow to wherever that winding will take it. (well, not so happy when certain V's are exceeded, perhaps:) Huh, wouldn't the transformer store energy more like a spring does, after all the schematic symbols are very similar? If "the transformer actually stores energy comparable to a fast rotating heavy object" wouldn't that cause a 6 dB/octave roll-off, resulting in a serious loss of high frequencies? Regards, John Byrns -- Surf my web pages at, http://fmamradios.com/ Yes it does. This is from the leakage inductance. Things come to a complete stop when leakage L and capacitance resonate...:) We specify a well designed and wound transformer with low leakage inductance so that it doesn't cause high frequency roll-off problems until well above the audio range. The impact of excess leakage inductance is also minimized by using a pentode output tube, which given your name I am sure you know all about. Regards, John Byrns -- Surf my web pages at, http://fmamradios.com/ |
Output classes A and AB
Rudy wrote: "Patrick Turner" wrote in message ... : : : Rudy wrote: : : "John Byrns" wrote in message : ... : : In article .com, : : Andre Jute wrote: : : : : On Oct 25, 7:40 am, Eeyore : : wrote: : : : : I'd love to know how that happens. There's no cancellation of ANYTHING : once : : one : : side has ceased conducting ! : : : : Graham : : : : Holy ****! Did I say yet that Poopie is ignorant and incompetent? : : : : Nah, nobody can be that stupid and uninformed about tube basics. : : : : There are a lot of "stupid and uninformed" people around, there are at : : least three people involved in this discussion that have expressed this : : same belief as Eeyore, they are Multi-grid, Patrick Turner, and Eeyore. : : : : : : Regards, : : : : John Byrns : : it seems the error made is in using the wrong mental model, that is : seeing the transformer primary as a resistance. : : To the vacuum tubes, RLa-a IS a resistance. for the purpose of loadline analyses, that is a fair approximation. for analyzing the actual working mechanism, it lacks accounting for the element of time, as the transformer actually stores energy comparable to a fast rotating heavy object storing rotational impulse so in case a tube is cutoff, it's plate will happily follow to wherever that winding will take it. (well, not so happy when certain V's are exceeded, perhaps:) The analogy is fine, as long as you remember there is no such thing as momentum in electronics. the output result will just be more or less symmetrically compressed, 3H, 5H, etc. this is distinctly different from a transistor PP, mostly apparent when you think of asymmetrical signals (music) driving it ;-) Asymetrical music signals will still have a dc content of zero, and there's very nearly always equal energy each side of zero. In a bjt output stage or a tube stage where the load is taken from the junction of the two output bjts or tubes, the Fourier waves are shunting one another, rather than being applied common mode as John B is so adament about. If one device is omitted, the class B waves are like you get with an SE tube biased on the brink of cut off. the load each PP tube sees is not suddenly changed at cutoff, it is in fact only balanced somewhat is a small region around the bias point, as with larger swing the dynamic plate resistance will vary more between the tubes, 3H will start to appear a measure of 'true class A' power of an AB pp, meaning the 3H would be low without nfb, would be the region where current is below twice the bias and cutoff AND dynamic plate R of the output tubes doesn't change more than "X" percent. Hmm, a little hard to follow you, but while a tube is cut off there is *no load* connected to it, unless in other words we say the Fourier currents all add to zero current for 1/2 a wave and are flowing in tube and 1/2 the OPT, but are conveniently summing to 0.0amps dc or ac for that 1/2 cycle. Usually 3H is HIGH witout NFB and unacceptably high when tubes are biased for class B at low levels, then as PO increases the % reduces, then inceases again near clipping. This was a problem with early SS amps; the early designers didn't know how to deal with the SS distortions at low levels where tube amps at the same level were much freer from distortions, and spectra was benign. The early designers could not afford to have hot idling class AB stages because germanium transistors went phut all too easily when they got hot. So they were forced int making all their crummy creations using class B working, and with token idle current. Bean counters made damn well sure OPTs were damn well eliminated from the SS amps during the transition from tubes to SS. For awhile, input transformers on SS amps were used because of the appallingly low base input resistance of the early power transistors, and besides, there were lots of out of work OPT winders available to wind simpler cheap IPT for SS to fill them in until permanent retrenchment, retirement or the sack. The appalling design ideas carried over into the days of early silicon bjts which turned out to be much more rugged than the germanium types. But SS heralded the use of class B, and the use of ever increasing amounts of NFB, so that we have amps with 40dB of local series voltage NFB in the form of emitter follower connection, and another 60dB of global NFB, to crossover distortion is difficult to identify as a spurious artifact amoungst the macro 3H and 2H which dominate the THD spectra just below clipping, but which rarely exceed 0.005% if the designer knows his stuff. In effct, many VAS stages in SS amps are merely a gain bjt with CC collector load to power a relaetively high impedance base input impedance of darligton output stage device arrays. The Single Ended VAS stage often has gain = 5,000x, and THD of this stage is say 5% at say 25Vrms, mainly 2H and 3H, very much like a pentode's spectra. The VAS stage THD well exceeds the output stage THD because of the emitter follower NFB. The 60dB of global NFB reduces the 5% of VAS thd to 0.005%. Because tubes have lower gain when used in audio circuits than available with bjts, and because of stability reasons, a large amount of NFB cannot be applied, with a total of 40 dB being about the limit. Patrick Turner. ... to be discussed, heh, Rudy : : One R set up set up with a CT so any signal voltage applied between the : end and the CT : is applied in opposite phase to the other end, courtesy of the action of : the transformer. : : Its RL a-a. : : This transformed single R appears to the tubes somewhat variably. : In class B, while a tube is conducting, the load on the tube is 1/4 : RLa-a, : and when both conduct in class A the load on each tube is 1/2RLa-a. : : The secondary R load is always reflected to the two tubes as RLa-a, with : a CT. : The Ra of the tubes seen at the secondary varies. : : Say you have Ra = 1.2k for EL34 in triode, and 6k:6 ohms OPT. ZR = : 1,000:1 : In class A, Ra-a = 2.4k and is transformed to 2.4ohms by the OPT. : In class B, only one tube is connected via 1/2 the primary, so only one : Ra = 1.2k : and OPT Z ratio has changed to 1.5k:6, because 1/2 the OPT primary isn't : operating : because one tube is cut off, so turn ratio is halved, Z ratio Ra in : class B = 1.5k/6 = 250, : so Ra at the output = 1.5k/250 = 6 ohms. : : The Rout of the amplifier at the sec is Ra transformed, and notice the : change in Rout : between A and AB. Its responsible for major 3H, 5H and other : distortions. : : : : sure, PP operating on a pure R load would cease to : cancel when one side would be cutoff, as it would no longer : partake in the transfer curve for PP ! : with a transformer, however, the transfer curve is a function : of the tight coupling of the primary halves, so always PP ;-) : (not the current, but the core flux is what matters) : : If one runs a class B PP amp with only ONE output tube, : you will get a badly distorted signal like the one you'd get : with a pure un-magnetically coupled R between B+ and the anode, : only at each end of the OPT pri there would be two phases of the same : distorted signal. : The load with one tube and OPT is the same as with a single R taken to a : suitably higher B+ : than used with an OPT. : : Fourier could describe what harmonics flow all the time despite cut off. : : Furious arguemnts have followed about him. : : Patrick Turner. : : : Rudy |
Output classes A and AB
John Byrns wrote:
Rudy wrote: for the purpose of loadline analyses, that is a fair approximation. for analyzing the actual working mechanism, it lacks accounting for the element of time, as the transformer actually stores energy comparable to a fast rotating heavy object storing rotational impulse so in case a tube is cutoff, it's plate will happily follow to wherever that winding will take it. (well, not so happy when certain V's are exceeded, perhaps:) : Huh, wouldn't the transformer store energy more like a spring does, : after all the schematic symbols are very similar? A capacitor is analogous to a spring. Don't be fooled by the symbols. A resistor is analogous to a damper, incidentally. : If "the transformer actually stores energy comparable to a fast rotating : heavy object" wouldn't that cause a 6 dB/octave roll-off, resulting in a : serious loss of high frequencies? Low frequencies, considering the mass is in shunt. Yes, it does. The concept of momentum in electronics is a bit interesting. Is LI concerved? If I have a perfect inductor passing current in a loop, and switch a second, equal, inductor into the circuit in series with the first, will the current be halved? If instead I double the inductance by inserting a core into the first inductor, will the current be also halved? In both cases large voltages would accompany the change, analogous to collision forces. Ian |
Output classes A and AB
In article ,
"Ian Iveson" wrote: John Byrns wrote: Rudy wrote: for the purpose of loadline analyses, that is a fair approximation. for analyzing the actual working mechanism, it lacks accounting for the element of time, as the transformer actually stores energy comparable to a fast rotating heavy object storing rotational impulse so in case a tube is cutoff, it's plate will happily follow to wherever that winding will take it. (well, not so happy when certain V's are exceeded, perhaps:) : Huh, wouldn't the transformer store energy more like a spring does, : after all the schematic symbols are very similar? A capacitor is analogous to a spring. Don't be fooled by the symbols. A resistor is analogous to a damper, incidentally. It depends on which dual you are using, an inductor can also be analogous to a spring and a capacitor to a mass. Regards, John Byrns -- Surf my web pages at, http://fmamradios.com/ |
Output classes A and AB
On Thu, 01 Nov 2007 12:26:01 -0500, John Byrns
wrote: In article , "Ian Iveson" wrote: John Byrns wrote: Rudy wrote: for the purpose of loadline analyses, that is a fair approximation. for analyzing the actual working mechanism, it lacks accounting for the element of time, as the transformer actually stores energy comparable to a fast rotating heavy object storing rotational impulse so in case a tube is cutoff, it's plate will happily follow to wherever that winding will take it. (well, not so happy when certain V's are exceeded, perhaps:) : Huh, wouldn't the transformer store energy more like a spring does, : after all the schematic symbols are very similar? A capacitor is analogous to a spring. Don't be fooled by the symbols. A resistor is analogous to a damper, incidentally. It depends on which dual you are using, an inductor can also be analogous to a spring and a capacitor to a mass. Regards, John Byrns I haven't given this any thought, but my intuition says that when you give an inductor a kick with a voltage, it is reluctant to get moving (current flow), which makes it more like the mass. How would you intuit that the other way? d -- Pearce Consulting http://www.pearce.uk.com |
Output classes A and AB
On Thu, 01 Nov 2007 13:40:47 -0500, John Byrns
wrote: In article , (Don Pearce) wrote: On Thu, 01 Nov 2007 12:26:01 -0500, John Byrns wrote: In article , "Ian Iveson" wrote: John Byrns wrote: Rudy wrote: for the purpose of loadline analyses, that is a fair approximation. for analyzing the actual working mechanism, it lacks accounting for the element of time, as the transformer actually stores energy comparable to a fast rotating heavy object storing rotational impulse so in case a tube is cutoff, it's plate will happily follow to wherever that winding will take it. (well, not so happy when certain V's are exceeded, perhaps:) : Huh, wouldn't the transformer store energy more like a spring does, : after all the schematic symbols are very similar? A capacitor is analogous to a spring. Don't be fooled by the symbols. A resistor is analogous to a damper, incidentally. It depends on which dual you are using, an inductor can also be analogous to a spring and a capacitor to a mass. Regards, John Byrns I haven't given this any thought, but my intuition says that when you give an inductor a kick with a voltage, it is reluctant to get moving (current flow), which makes it more like the mass. How would you intuit that the other way? It all depends on whether you are using the Force-voltage analogy or the Force-current analogy. Similarly you can redraw a purely electrical circuit so that all the capacitors become inductors, the inductors become capacitors, the resistors become conductances, voltages become currents, and currents become voltages. Thought you might say that! No, I've never bought into the notion of current causing voltage, it is always the other way round in my head. You apply a voltage, and a current results. d -- Pearce Consulting http://www.pearce.uk.com |
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