Hello valve lovers, wherever you are.
"Stewart Pinkerton" wrote in message
...
On Thu, 24 Jul 2003 14:57:41 +0100, "Keith G"
wrote:
Tell me if this will work: The amp has two sets of speaker outlets (A and
B)
which I have used to check the 'biwiring' phenomenon (to absolutely
'zero'
effect, I would say, yet again). If I use two pairs of (identical)
speaker
wires to the speakers and leave the connecting links on the speaker
terminals will I be able to select A and B in turn (ie to compare the
'with'
and 'without' resistors in series) or will the impedances be somehow
'messed
up'? (It would be a simple front-panel button pressing exercise if this
is
permissible....)
That should work, but it will also work if you just use the one cable,
and link the resistors between the A and B output terminals. This
reduvces the number of variables to just the resistor.
OK, this sounds neat and 'elegant' - better than wires running everywhere.
Correct me if I'm not getting this right - connect a cable like the letter
'h' where the speakers are off to the top and terminal A is the 'left foot'
and terminal B is the 'right foot' of the 'h'. The resistor (I have managed
to get a couple of R47Js rated at 4W - I take it these will be OK?) is then
chopped into the 'loop' between A and B.
Now, assuming I've got that right, selecting A will be equal to the cable
without the resistor and selecting B will include the resistor, yes? Will
that work OK and the fact that both A and B connections exist (but not
simultaneously selected, of course) throughout not 'muddy the waters' at
all? The geezer I got the resistors from went over my head with summat about
the amp being wired 'in series' internally?????
Off out for a while, will be playing with this later - listen out for the
'bang'........
:-)
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